Integrand size = 20, antiderivative size = 42 \[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\frac {18^n x^{1+m} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},\frac {4 a^2 x^2}{9}\right )}{1+m} \]
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Time = 0.01 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {126, 371} \[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\frac {18^n x^{m+1} \operatorname {Hypergeometric2F1}\left (\frac {m+1}{2},-n,\frac {m+3}{2},\frac {4 a^2 x^2}{9}\right )}{m+1} \]
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Rule 126
Rule 371
Rubi steps \begin{align*} \text {integral}& = \int x^m \left (18-8 a^2 x^2\right )^n \, dx \\ & = \frac {18^n x^{1+m} \, _2F_1\left (\frac {1+m}{2},-n;\frac {3+m}{2};\frac {4 a^2 x^2}{9}\right )}{1+m} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.64 \[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\frac {x^{1+m} (54-36 a x)^n (6+4 a x)^n \left (18-8 a^2 x^2\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},\frac {4 a^2 x^2}{9}\right )}{1+m} \]
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\[\int x^{m} \left (-2 a x +3\right )^{n} \left (4 a x +6\right )^{n}d x\]
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\[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\int { {\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n} x^{m} \,d x } \]
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Result contains complex when optimal does not.
Time = 16.09 (sec) , antiderivative size = 241, normalized size of antiderivative = 5.74 \[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=- \frac {3 \cdot 18^{n} 4^{- \frac {m}{2}} \cdot 9^{\frac {m}{2}} a^{- m - 1} {G_{6, 6}^{5, 3}\left (\begin {matrix} - \frac {m}{2} - \frac {n}{2}, - \frac {m}{2} - \frac {n}{2} + \frac {1}{2}, 1 & \frac {1}{2} - \frac {m}{2}, - \frac {m}{2} - n, - \frac {m}{2} - n + \frac {1}{2} \\- \frac {m}{2} - n - \frac {1}{2}, - \frac {m}{2} - n, - \frac {m}{2} - \frac {n}{2}, - \frac {m}{2} - n + \frac {1}{2}, - \frac {m}{2} - \frac {n}{2} + \frac {1}{2} & 0 \end {matrix} \middle | {\frac {9}{4 a^{2} x^{2}}} \right )} e^{i \pi n}}{8 \pi \Gamma \left (- n\right )} + \frac {3 \cdot 18^{n} 4^{- \frac {m}{2}} \cdot 9^{\frac {m}{2}} a^{- m - 1} {G_{6, 6}^{2, 6}\left (\begin {matrix} - \frac {m}{2} - \frac {1}{2}, - \frac {m}{2}, \frac {1}{2} - \frac {m}{2}, - \frac {m}{2} - \frac {n}{2} - \frac {1}{2}, - \frac {m}{2} - \frac {n}{2}, 1 & \\- \frac {m}{2} - \frac {n}{2} - \frac {1}{2}, - \frac {m}{2} - \frac {n}{2} & - \frac {m}{2} - \frac {1}{2}, - \frac {m}{2}, - \frac {m}{2} - n - \frac {1}{2}, 0 \end {matrix} \middle | {\frac {9 e^{- 2 i \pi }}{4 a^{2} x^{2}}} \right )} e^{- i \pi m}}{8 \pi \Gamma \left (- n\right )} \]
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\[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\int { {\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n} x^{m} \,d x } \]
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\[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\int { {\left (4 \, a x + 6\right )}^{n} {\left (-2 \, a x + 3\right )}^{n} x^{m} \,d x } \]
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Timed out. \[ \int x^m (3-2 a x)^n (6+4 a x)^n \, dx=\int x^m\,{\left (3-2\,a\,x\right )}^n\,{\left (4\,a\,x+6\right )}^n \,d x \]
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